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2.03x^2-17.26x-9.14=0
a = 2.03; b = -17.26; c = -9.14;
Δ = b2-4ac
Δ = -17.262-4·2.03·(-9.14)
Δ = 372.1244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17.26)-\sqrt{372.1244}}{2*2.03}=\frac{17.26-\sqrt{372.1244}}{4.06} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17.26)+\sqrt{372.1244}}{2*2.03}=\frac{17.26+\sqrt{372.1244}}{4.06} $
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